Add solutions for round 171
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7
codeforces/round-171/problem_a/Cargo.lock
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codeforces/round-171/problem_a/Cargo.lock
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# This file is automatically @generated by Cargo.
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# It is not intended for manual editing.
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version = 3
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[[package]]
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name = "problem_a"
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version = "0.1.0"
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6
codeforces/round-171/problem_a/Cargo.toml
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6
codeforces/round-171/problem_a/Cargo.toml
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[package]
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name = "problem_a"
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version = "0.1.0"
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edition = "2021"
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[dependencies]
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60
codeforces/round-171/problem_a/README.md
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codeforces/round-171/problem_a/README.md
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# A. Perpendicular Segments
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[Codeforces](https://codeforces.com/contest/2026/problem/A)
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You are given a coordinate plane and three integers `X`, `Y`, and `K`. Find two line segments `AB` and `CD` such that
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1. the coordinates of points `A`, `B`, `C`, and `D` are integers;
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2. 0 ≤ `Ax`, `Bx`, `Cx`, `Dx` ≤ `X` and 0 ≤ `Ay`, `By`, `Cy`, `Dy` ≤ `Y`;
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3. the length of segment `AB` is at least `K`;
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4. the length of segment `CD` is at least `K`;
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5. segments `AB` and `CD` are perpendicular: if you draw lines that contain `AB` and `CD`, they will cross at a right angle.
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Note that it's not necessary for segments to intersect.
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Segments are perpendicular as long as the lines they induce are perpendicular.
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## Input
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The first line contains a single integer `t` (1 ≤ `t` ≤ 5000) — the number of test cases. Next, `t` cases follow.
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The first and only line of each test case contains three integers `X`, `Y`, and `K`
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(1 ≤ `X`, `Y` ≤ 1000; 1 ≤ `K`≤ 1414).
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Additional constraint on the input: the values of `X`, `Y`, and `K`
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are chosen in such a way that the answer exists.
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## Output
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For each test case, print two lines. The first line should contain 4
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integers `Ax`, `Ay`, `Bx`, and `By` — the coordinates of the first segment.
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The second line should also contain 4
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integers `Cx`, `Cy`, `Dx`, and `Dy` — the coordinates of the second segment.
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If there are multiple answers, print any of them.
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## Example
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Input
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```
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4
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1 1 1
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3 4 1
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4 3 3
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3 4 4
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```
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Output
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```
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0 0 1 0
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0 0 0 1
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2 4 2 2
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0 1 1 1
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0 0 1 3
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1 2 4 1
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0 1 3 4
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0 3 3 0
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```
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codeforces/round-171/problem_a/src/main.rs
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codeforces/round-171/problem_a/src/main.rs
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use std::cmp;
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use std::io;
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struct Segment {
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start: Point,
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end: Point,
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}
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struct Point {
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x: u64,
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y: u64,
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}
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fn gen_segments(x: u64, y: u64, _k: u64) -> Vec<Segment> {
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let min_coord = cmp::min(x, y);
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vec!(
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Segment{start: Point{x: 0, y: 0}, end: Point{x: min_coord, y: min_coord}},
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Segment{start: Point{x: 0, y: min_coord}, end: Point{x: min_coord, y: 0}},
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)
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}
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fn main() {
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let stdin = io::stdin();
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let mut buffer = String::new();
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stdin.read_line(&mut buffer).unwrap();
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let n: u64 = buffer.trim().parse().unwrap();
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for _i in 0..n {
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buffer = String::from("");
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stdin.read_line(&mut buffer).unwrap();
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let nums = buffer
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.trim()
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.split_whitespace()
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.map(|s| s.parse::<u64>().unwrap())
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.collect::<Vec<u64>>();
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for segment in gen_segments(nums[0], nums[1], nums[2]) {
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println!("{} {} {} {}", segment.start.x, segment.start.y, segment.end.x, segment.end.y);
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}
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}
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}
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7
codeforces/round-171/problem_b/Cargo.lock
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7
codeforces/round-171/problem_b/Cargo.lock
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# This file is automatically @generated by Cargo.
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# It is not intended for manual editing.
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version = 3
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[[package]]
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name = "problem_b"
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version = "0.1.0"
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6
codeforces/round-171/problem_b/Cargo.toml
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6
codeforces/round-171/problem_b/Cargo.toml
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[package]
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name = "problem_b"
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version = "0.1.0"
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edition = "2021"
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[dependencies]
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codeforces/round-171/problem_b/README.md
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codeforces/round-171/problem_b/README.md
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# B. Black Cells
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[Codeforces](https://codeforces.com/contest/2026/problem/B)
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You are given a strip divided into cells, numbered from left to right from 0 to 1018. Initially, all cells are white.
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You can perform the following operation: choose two white cells `i` and `j`,
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such that `i` ≠ `j` and |`i` − `j`| ≤ `k`, and paint them black.
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A list `a` is given. All cells from this list must be painted black.
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Additionally, at most one cell that is not in this list can also be painted black.
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Your task is to determine the minimum value of `k` for which this is possible.
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## Input
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The first line contains a single integer `t` (1 ≤ `t` ≤ 500) — the number of test cases.
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The first line of each test case contains a single integer `n` (1 ≤ `n` ≤ 2000).
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The second line contains `n` integers `a1`, `a2`, ... , `an` (0 < `ai`< 1018; `ai` < `ai` + 1).
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Additional constraint on the input: the sum of `n` across all test cases does not exceed 2000.
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## Output
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For each test case, print a single integer — the minimum value of `k`
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for which it is possible to paint all the given cells black.
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## Example
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Input
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```
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4
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2
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1 2
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1
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7
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3
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2 4 9
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5
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1 5 8 10 13
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```
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Output
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```
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1
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1
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2
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3
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```
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## Note
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In the first example, with `k` = 1 , it is possible to paint the cells (1, 2).
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In the second example, with `k` = 1, it is possible to paint the cells (7, 8).
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In the third example, with `k` = 2, it is possible to paint the cells (2, 4) and (8, 9).
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In the fourth example, with `k` = 3, it is possible to paint the cells (0, 1), (5, 8) and (10, 13).
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codeforces/round-171/problem_b/src/main.rs
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codeforces/round-171/problem_b/src/main.rs
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use std::io;
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fn get_max_distance(nums: Vec<u64>) -> u64 {
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let mut max_distance = 0;
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let mut i = 0;
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while i + 1 < nums.len() {
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let dist = nums[i + 1] - nums[i];
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if dist > max_distance {
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max_distance = dist;
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}
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i += 2;
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}
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max_distance
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}
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fn get_min_k(nums: Vec<u64>) -> u64 {
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if nums.len() <= 1 {
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return 1;
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}
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if nums.len() % 2 == 0 {
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return get_max_distance(nums);
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}
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let mut min_k = nums.last().unwrap() - nums[0];
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for skip_idx in 0..nums.len() {
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let mut subset = nums.clone();
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subset.remove(skip_idx);
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let k = get_max_distance(subset);
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if k < min_k {
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min_k = k;
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}
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}
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min_k
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}
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fn main() {
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let stdin = io::stdin();
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let mut buffer = String::new();
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let _ = stdin.read_line(&mut buffer);
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let t: u64 = buffer.trim().parse().unwrap();
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for _i in 0..t {
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let _ = stdin.read_line(&mut buffer);
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buffer = String::from("");
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let _ = stdin.read_line(&mut buffer);
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let nums = buffer
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.trim()
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.split_whitespace()
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.map(|s| s.parse::<u64>().unwrap())
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.collect::<Vec<u64>>();
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println!("{}", get_min_k(nums));
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}
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}
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#[cfg(test)]
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mod tests {
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use super::*;
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#[test]
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fn test_samples() {
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assert_eq!(get_min_k(vec!(1, 2)), 1);
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assert_eq!(get_min_k(vec!(7)), 1);
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assert_eq!(get_min_k(vec!(2, 4, 9)), 2);
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assert_eq!(get_min_k(vec!(1, 5, 8, 10, 13)), 3);
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assert_eq!(get_min_k(vec!(1, 5, 8, 40, 43)), 3);
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assert_eq!(get_min_k(vec!(5, 8, 20, 40, 43)), 3);
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assert_eq!(get_min_k(vec!(1, 3)), 2);
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}
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}
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