diff --git a/codeforces/round-171/problem_a/Cargo.lock b/codeforces/round-171/problem_a/Cargo.lock
new file mode 100644
index 0000000..0288093
--- /dev/null
+++ b/codeforces/round-171/problem_a/Cargo.lock
@@ -0,0 +1,7 @@
+# This file is automatically @generated by Cargo.
+# It is not intended for manual editing.
+version = 3
+
+[[package]]
+name = "problem_a"
+version = "0.1.0"
diff --git a/codeforces/round-171/problem_a/Cargo.toml b/codeforces/round-171/problem_a/Cargo.toml
new file mode 100644
index 0000000..ddb6f5a
--- /dev/null
+++ b/codeforces/round-171/problem_a/Cargo.toml
@@ -0,0 +1,6 @@
+[package]
+name = "problem_a"
+version = "0.1.0"
+edition = "2021"
+
+[dependencies]
diff --git a/codeforces/round-171/problem_a/README.md b/codeforces/round-171/problem_a/README.md
new file mode 100644
index 0000000..4adb812
--- /dev/null
+++ b/codeforces/round-171/problem_a/README.md
@@ -0,0 +1,60 @@
+# A. Perpendicular Segments
+
+[Codeforces](https://codeforces.com/contest/2026/problem/A)
+
+You are given a coordinate plane and three integers `X`, `Y`, and `K`. Find two line segments `AB` and `CD` such that
+
+1. the coordinates of points `A`, `B`, `C`, and `D` are integers;
+2. 0 ≤ `Ax`, `Bx`, `Cx`, `Dx` ≤ `X` and 0 ≤ `Ay`, `By`, `Cy`, `Dy` ≤ `Y`;
+3. the length of segment `AB` is at least `K`;
+4. the length of segment `CD` is at least `K`;
+5. segments `AB` and `CD` are perpendicular: if you draw lines that contain `AB` and `CD`, they will cross at a right angle. 
+
+Note that it's not necessary for segments to intersect.
+Segments are perpendicular as long as the lines they induce are perpendicular.
+
+
+## Input
+
+The first line contains a single integer `t` (1 ≤ `t` ≤ 5000) — the number of test cases. Next, `t` cases follow.
+
+The first and only line of each test case contains three integers `X`, `Y`, and `K`
+(1 ≤ `X`, `Y` ≤ 1000; 1 ≤ `K`≤ 1414).
+
+Additional constraint on the input: the values of `X`, `Y`, and `K`
+are chosen in such a way that the answer exists.
+
+## Output
+
+For each test case, print two lines. The first line should contain 4
+integers `Ax`, `Ay`, `Bx`, and `By` — the coordinates of the first segment.
+
+The second line should also contain 4
+integers `Cx`, `Cy`, `Dx`, and `Dy` — the coordinates of the second segment.
+
+If there are multiple answers, print any of them.
+
+## Example
+
+Input
+
+```
+4
+1 1 1
+3 4 1
+4 3 3
+3 4 4
+```
+
+Output
+
+```
+0 0 1 0
+0 0 0 1
+2 4 2 2
+0 1 1 1
+0 0 1 3
+1 2 4 1
+0 1 3 4
+0 3 3 0
+```
diff --git a/codeforces/round-171/problem_a/src/main.rs b/codeforces/round-171/problem_a/src/main.rs
new file mode 100644
index 0000000..d29d411
--- /dev/null
+++ b/codeforces/round-171/problem_a/src/main.rs
@@ -0,0 +1,41 @@
+use std::cmp;
+use std::io;
+
+struct Segment {
+    start: Point,
+    end: Point,
+}
+
+struct Point {
+    x: u64,
+    y: u64,
+}
+
+fn gen_segments(x: u64, y: u64, _k: u64) -> Vec<Segment> {
+    let min_coord = cmp::min(x, y);
+    vec!(
+        Segment{start: Point{x: 0, y: 0}, end: Point{x: min_coord, y: min_coord}},
+        Segment{start: Point{x: 0, y: min_coord}, end: Point{x: min_coord, y: 0}},
+    )
+}
+
+fn main() {
+    let stdin = io::stdin();
+    let mut buffer = String::new();
+
+    stdin.read_line(&mut buffer).unwrap();
+    let n: u64 = buffer.trim().parse().unwrap();
+
+    for _i in 0..n {
+        buffer = String::from("");
+        stdin.read_line(&mut buffer).unwrap();
+        let nums = buffer
+            .trim()
+            .split_whitespace()
+            .map(|s| s.parse::<u64>().unwrap())
+            .collect::<Vec<u64>>();
+        for segment in gen_segments(nums[0], nums[1], nums[2]) {
+            println!("{} {} {} {}", segment.start.x, segment.start.y, segment.end.x, segment.end.y);
+        }
+    }
+}
diff --git a/codeforces/round-171/problem_b/Cargo.lock b/codeforces/round-171/problem_b/Cargo.lock
new file mode 100644
index 0000000..59c7ecd
--- /dev/null
+++ b/codeforces/round-171/problem_b/Cargo.lock
@@ -0,0 +1,7 @@
+# This file is automatically @generated by Cargo.
+# It is not intended for manual editing.
+version = 3
+
+[[package]]
+name = "problem_b"
+version = "0.1.0"
diff --git a/codeforces/round-171/problem_b/Cargo.toml b/codeforces/round-171/problem_b/Cargo.toml
new file mode 100644
index 0000000..fbd01f1
--- /dev/null
+++ b/codeforces/round-171/problem_b/Cargo.toml
@@ -0,0 +1,6 @@
+[package]
+name = "problem_b"
+version = "0.1.0"
+edition = "2021"
+
+[dependencies]
diff --git a/codeforces/round-171/problem_b/README.md b/codeforces/round-171/problem_b/README.md
new file mode 100644
index 0000000..8e584cc
--- /dev/null
+++ b/codeforces/round-171/problem_b/README.md
@@ -0,0 +1,65 @@
+# B. Black Cells
+
+[Codeforces](https://codeforces.com/contest/2026/problem/B)
+
+You are given a strip divided into cells, numbered from left to right from 0 to 1018. Initially, all cells are white.
+
+You can perform the following operation: choose two white cells `i` and `j`,
+such that `i` ≠ `j` and |`i` − `j`| ≤ `k`, and paint them black.
+
+A list `a` is given. All cells from this list must be painted black.
+Additionally, at most one cell that is not in this list can also be painted black.
+Your task is to determine the minimum value of `k` for which this is possible.
+
+
+## Input
+
+The first line contains a single integer `t` (1 ≤ `t` ≤ 500) — the number of test cases.
+
+The first line of each test case contains a single integer `n` (1 ≤ `n` ≤ 2000).
+
+The second line contains `n` integers `a1`, `a2`, ... , `an` (0 < `ai`< 1018; `ai` < `ai` + 1).
+
+Additional constraint on the input: the sum of `n` across all test cases does not exceed 2000.
+
+
+## Output
+
+For each test case, print a single integer — the minimum value of `k`
+for which it is possible to paint all the given cells black.
+
+
+## Example
+Input
+
+```
+4
+2
+1 2
+1
+7
+3
+2 4 9
+5
+1 5 8 10 13
+```
+
+Output
+
+```
+1
+1
+2
+3
+```
+
+
+## Note
+
+In the first example, with `k` = 1 , it is possible to paint the cells (1, 2).
+
+In the second example, with `k` = 1, it is possible to paint the cells (7, 8).
+
+In the third example, with `k` = 2, it is possible to paint the cells (2, 4) and (8, 9).
+
+In the fourth example, with `k` = 3, it is possible to paint the cells (0, 1), (5, 8) and (10, 13).
diff --git a/codeforces/round-171/problem_b/src/main.rs b/codeforces/round-171/problem_b/src/main.rs
new file mode 100644
index 0000000..8fded57
--- /dev/null
+++ b/codeforces/round-171/problem_b/src/main.rs
@@ -0,0 +1,74 @@
+use std::io;
+
+fn get_max_distance(nums: Vec<u64>) -> u64 {
+    let mut max_distance = 0;
+    let mut i = 0;
+    while i + 1 < nums.len() {
+        let dist = nums[i + 1] - nums[i];
+        if dist > max_distance {
+            max_distance = dist;
+        }
+        i += 2;
+    }
+
+    max_distance
+}
+
+fn get_min_k(nums: Vec<u64>) -> u64 {
+    if nums.len() <= 1 {
+        return 1;
+    }
+
+    if nums.len() % 2 == 0 {
+        return get_max_distance(nums);
+    }
+
+    let mut min_k = nums.last().unwrap() - nums[0];
+    for skip_idx in 0..nums.len() {
+        let mut subset = nums.clone();
+        subset.remove(skip_idx);
+        let k = get_max_distance(subset);
+        if k < min_k {
+            min_k = k;
+        }
+    }
+
+    min_k
+}
+
+fn main() {
+    let stdin = io::stdin();
+    let mut buffer = String::new();
+
+    let _ = stdin.read_line(&mut buffer);
+    let t: u64 = buffer.trim().parse().unwrap();
+
+    for _i in 0..t {
+        let _ = stdin.read_line(&mut buffer);
+        buffer = String::from("");
+
+        let _ = stdin.read_line(&mut buffer);
+        let nums = buffer
+            .trim()
+            .split_whitespace()
+            .map(|s| s.parse::<u64>().unwrap())
+            .collect::<Vec<u64>>();
+        println!("{}", get_min_k(nums));
+    }
+}
+
+#[cfg(test)]
+mod tests {
+    use super::*;
+
+    #[test]
+    fn test_samples() {
+        assert_eq!(get_min_k(vec!(1, 2)), 1);
+        assert_eq!(get_min_k(vec!(7)), 1);
+        assert_eq!(get_min_k(vec!(2, 4, 9)), 2);
+        assert_eq!(get_min_k(vec!(1, 5, 8, 10, 13)), 3);
+        assert_eq!(get_min_k(vec!(1, 5, 8, 40, 43)), 3);
+        assert_eq!(get_min_k(vec!(5, 8, 20, 40, 43)), 3);
+        assert_eq!(get_min_k(vec!(1, 3)), 2);
+    }
+}