leetcode: solve 'container with most water' problem
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# Used by "mix format"
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[
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inputs: ["{mix,.formatter}.exs", "{config,lib,test}/**/*.{ex,exs}"]
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]
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leetcode/0011-container-with-most-water/elixir/.gitignore
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leetcode/0011-container-with-most-water/elixir/.gitignore
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# The directory Mix will write compiled artifacts to.
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/_build/
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# If you run "mix test --cover", coverage assets end up here.
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/cover/
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# The directory Mix downloads your dependencies sources to.
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/deps/
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# Where third-party dependencies like ExDoc output generated docs.
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/doc/
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# Ignore .fetch files in case you like to edit your project deps locally.
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/.fetch
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# If the VM crashes, it generates a dump, let's ignore it too.
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erl_crash.dump
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# Also ignore archive artifacts (built via "mix archive.build").
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*.ez
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# Ignore package tarball (built via "mix hex.build").
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solution-*.tar
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# Temporary files, for example, from tests.
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/tmp/
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defmodule Solution do
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@spec max_area(height :: [integer]) :: integer
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def max_area(height) do
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iter(0, height, 0, 0)
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end
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defp iter(prev, [head | tail], head_idx, max_vol) do
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if prev >= head do
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iter(prev, tail, head_idx + 1, max_vol)
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else
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max_vol = iter_inner(head, head_idx, tail, head_idx + 1, max_vol)
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iter(head, tail, head_idx + 1, max_vol)
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end
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end
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defp iter(_, [], _, max_vol), do: max_vol
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defp iter_inner(a, a_idx, [head | tail], head_idx, max_vol) do
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distance = head_idx - a_idx
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min_height = min(a, head)
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volume = min_height * distance
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max_vol = max(max_vol, volume)
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iter_inner(a, a_idx, tail, head_idx + 1, max_vol)
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end
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defp iter_inner(_, _, [], _, max_vol), do: max_vol
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end
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leetcode/0011-container-with-most-water/elixir/mix.exs
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leetcode/0011-container-with-most-water/elixir/mix.exs
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defmodule Solution.MixProject do
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use Mix.Project
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def project do
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[
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app: :solution,
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version: "0.1.0",
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elixir: "~> 1.16",
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start_permanent: Mix.env() == :prod,
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deps: deps()
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]
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end
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# Run "mix help compile.app" to learn about applications.
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def application do
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[
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extra_applications: [:logger]
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]
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end
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# Run "mix help deps" to learn about dependencies.
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defp deps do
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[
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# {:dep_from_hexpm, "~> 0.3.0"},
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# {:dep_from_git, git: "https://github.com/elixir-lang/my_dep.git", tag: "0.1.0"}
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]
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end
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end
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defmodule SolutionTest do
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use ExUnit.Case
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doctest Solution
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test "example 1" do
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assert Solution.max_area([1, 8, 6, 2, 5, 4, 8, 3, 7]) == 49
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end
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test "example 2" do
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assert Solution.max_area([1, 1]) == 1
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end
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test "large input" do
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length = Integer.pow(10, 7)
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input = Enum.map(1..length, fn _ -> :rand.uniform(10000) end)
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Solution.max_area(input)
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end
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end
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ExUnit.start()
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leetcode/0011-container-with-most-water/readme.md
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leetcode/0011-container-with-most-water/readme.md
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# 11. Container With Most Water
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[Leetcode](https://leetcode.com/problems/container-with-most-water/)
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You are given an integer array height of length n. There are n vertical lines drawn such that the two endpoints of the ith line are (i, 0) and (i, height[i]).
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Find two lines that together with the x-axis form a container, such that the container contains the most water.
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Return the maximum amount of water a container can store.
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Notice that you may not slant the container.
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